The potential energy (PE) lost by the particle is given by:

\(\text{PE loss} = mgh = 0.6 \times 10 \times 8 = 48 \text{ J}\)

The kinetic energy (KE) gained by the particle is given by:

\(\text{KE gain} = \frac{1}{2} mv^2 = \frac{1}{2} \times 0.6 \times 10^2 = 30 \text{ J}\)

The work done against air resistance is the difference between the potential energy lost and the kinetic energy gained:

\(\text{Work done against resistance} = 48 - 30 = 18 \text{ J}\)