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Nov 2002 p4 q1
3491
A car of mass 1000 kg travels along a horizontal straight road with its engine working at a constant rate of 20 kW. The resistance to motion of the car is 600 N. Find the acceleration of the car at an instant when its speed is 25 m s-1.
Solution
First, calculate the driving force using the power formula:
\(Power = Force × Velocity\)
\(Given power = 20,000 W and velocity = 25 m/s,\)
Driving force = \(\frac{20,000}{25} = 800 \text{ N}\).
Using Newton's second law, the net force is given by:
\(Net force = Driving force - Resistance = 800 - 600 = 200 \text{ N}.\)
According to Newton's second law, \(F = ma\), where \(F\) is the net force, \(m\) is the mass, and \(a\) is the acceleration.