First, calculate the driving force (DF) using the power formula:

\(\text{Power} = \text{Force} \times \text{Velocity}\)

\(35000 = \text{DF} \times 16\)

\(\text{DF} = \frac{35000}{16} = 2187.5 \text{ N}\)

Apply Newton's second law to find the acceleration:

\(\text{Net force} = \text{mass} \times \text{acceleration}\)

The net force is given by:

\(\text{DF} - 1150g \sin(1.2^{\circ}) - 975 = 1150a\)

Substitute the known values:

\(2187.5 - 1150 \times 9.8 \times \sin(1.2^{\circ}) - 975 = 1150a\)

Calculate the gravitational component:

\(1150 \times 9.8 \times \sin(1.2^{\circ}) \approx 235.8 \text{ N}\)

Substitute back:

\(2187.5 - 235.8 - 975 = 1150a\)

\(976.7 = 1150a\)

Solve for \(a\):

\(a = \frac{976.7}{1150} \approx 0.849 \text{ m s}^{-2}\)

Rounding to three significant figures gives:

\(a = 0.845 \text{ m s}^{-2}\)