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June 2011 p42 q1
3472
A load is pulled along horizontal ground for a distance of 76 m, using a rope. The rope is inclined at 5° above the horizontal and the tension in the rope is 65 N.
(i) Find the work done by the tension.
At an instant during the motion the velocity of the load is 1.5 m s-1.
(ii) Find the rate of working of the tension at this instant.
Solution
(i) The work done by the tension is given by the formula:
\(ext{Work Done} = T imes d imes ext{cos}( heta)\)
where \(T = 65 \text{ N}\), \(d = 76 \text{ m}\), and \(\theta = 5^{\circ}\).