(i) The driving force (DF) is given by the formula for power: \(P = Fv\), where \(P = 1500,000\) W and \(v = 37.5\) m/s. Thus, \(DF = \frac{1500,000}{37.5} = 40,000\) N.
Using Newton's second law, \(DF - R = ma\), where \(R = 30,000\) N and \(m = 400,000\) kg.
Substitute the values: \(40,000 - 30,000 = 400,000a\).
Solve for \(a\): \(10,000 = 400,000a\) gives \(a = 0.025\) m/s2.
(ii) For steady speed, acceleration \(a = 0\). Thus, \(DF - R = 0\).
\(\frac{1500,000}{v} - 30,000 = 0\).
Solve for \(v\): \(\frac{1500,000}{v} = 30,000\) gives \(v = 50\) m/s.