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Nov 2014 p41 q1
3456
A car of mass 800 kg is moving on a straight horizontal road with its engine working at a rate of 22.5 kW. Find the resistance to the car’s motion at an instant when the car’s speed is 18 m/s and its acceleration is 1.2 m/s2.
Solution
First, calculate the driving force (DF) using the power formula:
\(Power = Force × Velocity\)
\(Given power = 22.5 kW = 22500 W and velocity = 18 m/s,\)
DF = \(\frac{22500}{18} = 1250\) N
Using Newton's second law, the net force is given by: