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June 2018 p42 q2
3430
A train of mass 240,000 kg travels up a slope inclined at an angle of 4° to the horizontal. There is a constant resistance of magnitude 18,000 N acting on the train. At an instant when the speed of the train is 15 m/s, its deceleration is 0.2 m/s². Find the power of the engine of the train.
Solution
To find the power of the engine, we first need to determine the driving force (DF) using the equation for power:
\(DF = \frac{P}{v}\)
where \(P\) is the power and \(v = 15 \text{ m/s}\) is the speed of the train.
Using Newton's second law, the equation for the forces acting on the train is: