The power \(P\) of the crane is given by the formula \(P = Fv\), where \(F\) is the force and \(v\) is the velocity.

The force \(F\) required to lift the load is equal to the weight of the load, which is \(F = mg\), where \(m = 1250\) kg is the mass and \(g = 9.8\) m s^-2 is the acceleration due to gravity.

Thus, \(F = 1250 \times 9.8\).

Given that the power \(P = 20,000\) W (since 20 kW = 20,000 W), we have:

\(20,000 = V \times 1250 \times 9.8\).

Solving for \(V\):

\(V = \frac{20,000}{1250 \times 9.8}\).

\(V = 1.6\) m s^-1.