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June 2022 p43 q1
3381
Two particles P and Q, of masses 0.3 kg and 0.2 kg respectively, are at rest on a smooth horizontal plane. P is projected at a speed of 4 m s-1 directly towards Q. After P and Q collide, Q begins to move with a speed of 3 m s-1.
(a) Find the speed of P after the collision.
After the collision, Q moves directly towards a third particle R, of mass m kg, which is at rest on the plane. The two particles Q and R coalesce on impact and move with a speed of 2 m s-1.
(b) Find m.
Solution
(a) Using conservation of momentum for the collision between P and Q:
The initial momentum is given by:
\(0.3 \times 4 + 0 = 1.2 \text{ kg m s}^{-1}\)
The final momentum is:
\(0.3v + 0.2 \times 3\)
Equating initial and final momentum:
\(1.2 = 0.3v + 0.6\)
Solving for \(v\):
\(0.3v = 0.6\)
\(v = 2 \text{ m s}^{-1}\)
(b) Using conservation of momentum for the collision between Q and R: