The problem can be modeled using a binomial distribution with parameters:

- Number of trials, \(n = 365\) (days in a year) - Probability of success, \(p = 0.15\) (probability of eating potato)

The mean \(\mu\) and variance \(\sigma^2\) of the binomial distribution are given by:

\(\mu = np = 365 \times 0.15 = 54.75\)

\(\sigma^2 = np(1-p) = 365 \times 0.15 \times 0.85 = 46.5375\)

We approximate the binomial distribution with a normal distribution \(N(\mu, \sigma^2)\).

To find the probability that Annabel eats potato on more than 44 days, we standardize the variable:

\(P(X > 44) = P\left( Z > \frac{44.5 - 54.75}{\sqrt{46.5375}} \right)\)

\(= P(Z > -1.5025)\)

Using the standard normal distribution table, \(P(Z > -1.5025) = 0.933\).