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June 2023 p53 q6
3203
The mass of grapes sold per day by a large shop can be modelled by a normal distribution with mean 28 kg. On 10% of days less than 16 kg of grapes are sold.
(a) Find the standard deviation of the mass of grapes sold per day.
(c) In a random sample of 365 days, on how many days would you expect the mass of grapes sold to be within 1.3 standard deviations of the mean?
Solution
(a) We know that \(P(X < 16) = 0.1\). Using the standard normal distribution, we find the z-value corresponding to 0.1, which is approximately \(-1.282\).
Using the standardization formula:
\(\frac{16 - 28}{\sigma} = -1.282\)
Solving for \(\sigma\):
\(\sigma = \frac{12}{1.282} \approx 9.36\)
(c) We need to find \(P(-1.3 < Z < 1.3)\).
Using the standard normal distribution table, \(\Phi(1.3) \approx 0.9032\).