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June 2022 p51 q5
3175
The lengths of the leaves of another type are also modelled by a normal distribution. A scientist measures the lengths of a random sample of 500 leaves of this type and finds that 46 are less than 3 cm long and 95 are more than 8 cm long.
(b) Find estimates for the mean and standard deviation of the lengths of leaves of this type.
(c) In a random sample of 2000 leaves of this second type, how many would the scientist expect to find with lengths more than 1 standard deviation from the mean?
Solution
(b) We use the standard normal distribution to find the mean \(\mu\) and standard deviation \(\sigma\). Given:
\(z_1 = \frac{3 - \mu}{\sigma} = -1.329\)
\(z_2 = \frac{8 - \mu}{\sigma} = 0.878\)
Solving these equations simultaneously, we find:
\(\sigma = 2.27, \mu = 6.01\)
(c) To find the number of leaves more than 1 standard deviation from the mean, we calculate: