Find the set of values of p for which the equation \(4x^2 - 24x + p = 0\) has no real roots.
Solution
For the quadratic equation \(ax^2 + bx + c = 0\) to have no real roots, the discriminant must be less than zero.
The discriminant \(\Delta\) is given by \(b^2 - 4ac\).
Here, \(a = 4\), \(b = -24\), and \(c = p\).
So, \(\Delta = (-24)^2 - 4 \times 4 \times p\).
\(\Delta = 576 - 16p\).
For no real roots, \(576 - 16p < 0\).
Solving for \(p\):
\(576 < 16p\)
\(p > 36\)
Log in to record attempts.