Let the random variable \(X\) represent the height of the sunflowers, where \(X \sim N(112, 17.2^2)\).

We need to find \(P(X > 120)\).

First, standardize the variable:

\(Z = \frac{X - \mu}{\sigma} = \frac{120 - 112}{17.2} = 0.4651\)

Now, find the probability:

\(P(X > 120) = 1 - \Phi(0.4651)\)

Using standard normal distribution tables or a calculator, \(\Phi(0.4651) \approx 0.6790\).

Thus, \(P(X > 120) = 1 - 0.6790 = 0.321\)