Let \(X\) be the daily minimum temperature in January in Ottawa. We have \(X \sim N(-15.1, 62.0)\).

We need to find \(P(X > 0)\).

Standardize the variable:

\(Z = \frac{X - (-15.1)}{\sqrt{62}}\)

For \(X = 0\),

\(Z = \frac{0 - (-15.1)}{\sqrt{62}} = \frac{15.1}{\sqrt{62}} \approx 1.918\)

Using the standard normal distribution table, find \(\Phi(1.918) \approx 0.9724\).

Thus, \(P(X > 0) = 1 - \Phi(1.918) = 1 - 0.9724 = 0.0276\).