(i) To find the probability that a book is classified as large, we first standardize the height 29 cm using the normal distribution with mean 21.7 and standard deviation 6.5:

\(P(\text{large}) = 1 - \Phi\left(\frac{29 - 21.7}{6.5}\right)\)

\(= 1 - \Phi(1.123) = 1 - 0.8692 = 0.1308\)

Now, we use the binomial distribution to find the probability that fewer than 2 books are large out of 8:

\(P(0,1) = (0.8692)^8 + \binom{8}{1}(0.1308)(0.8692)^7\)

\(= 0.718\)

(ii) We need the probability of at least 1 large book to be more than 0.98. This is equivalent to:

\(1 - (0.8692)^n > 0.98\)

\((0.8692)^n < 0.02\)

Solving for the smallest integer \(n\), we find:

\(n = 28\)