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Nov 2015 p62 q7
3143
The random variable \(Y\) is normally distributed with mean \(\mu\) and standard deviation \(\sigma\). Given that \(\sigma = \frac{2}{3} \mu\), find the probability that a random value of \(Y\) is less than \(2\mu\).
Solution
We need to find \(P(Y < 2\mu)\). To do this, we standardize the variable using the formula for the standard normal distribution:
\(z = \frac{Y - \mu}{\sigma}\)
Substituting \(Y = 2\mu\), \(\mu\), and \(\sigma = \frac{2}{3} \mu\), we have: