Let the random variable representing the length of the snakes be denoted by \(X\), where \(X \sim N(54, 6.1^2)\).

We need to find \(P(50 < X < 60)\).

First, convert the lengths to standard normal variables \(Z\) using the formula:

\(Z = \frac{X - \mu}{\sigma}\)

For \(X = 50\):

\(Z = \frac{50 - 54}{6.1} = -0.6557\)

For \(X = 60\):

\(Z = \frac{60 - 54}{6.1} = 0.9836\)

Thus, we need to find \(P(-0.6557 < Z < 0.9836)\).

This is equivalent to \(\Phi(0.9836) - \Phi(-0.6557)\).

Using the standard normal distribution table:

\(\Phi(0.9836) = 0.8375\)

\(\Phi(-0.6557) = 1 - \Phi(0.6557) = 1 - 0.7441 = 0.2559\)

Therefore, \(P(-0.6557 < Z < 0.9836) = 0.8375 - 0.2559 = 0.5816\).

Rounding to three decimal places, the probability is \(0.582\).