(b) The probability that the first wet day is 8 October means that the first 7 days are dry and the 8th day is wet. The probability of a dry day is 1 - 0.16 = 0.84. Therefore, the probability is given by:

\((0.84)^7 \times 0.16 = 0.0472\)

(c) We need to find the probability that in exactly 1 out of 4 years, the first wet day is 8 October. Using the result from part (b), the probability for one year is 0.0472. The probability that this happens in exactly 1 out of 4 years is given by the binomial probability formula:

\(4 \times 0.0472 \times (1 - 0.0472)^3 = 0.163\)