The equation of a curve is \(y=4x^2+20x+6\).

(a) Express \(y\) in the form \(a(x+b)^2+c\), where \(a\), \(b\) and \(c\) are constants to be found. [3]

(b) Hence solve the equation \(4x^2+20x+6=45\). [3]

(c) Sketch the graph of \(y=4x^2+20x+6\) showing the coordinates of the stationary point. You are not required to indicate where the curve crosses the x- and y-axes. [3]