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June 2011 p61 q3
2967
The possible values of the random variable X are the 8 integers in the set \(\{-2, -1, 0, 1, 2, 3, 4, 5\}\). The probability of X being 0 is \(\frac{1}{10}\). The probabilities for all the other values of X are equal. Calculate:
\(P(X < 2)\),
the variance of X,
the value of a for which \(P(-a \leq X \leq 2a) = \frac{17}{35}\).
Solution
(i) The probability of any other number is \(\frac{9}{70}\). Therefore, \(P(X < 2) = \frac{27}{70} + \frac{1}{10} = \frac{34}{70} = \frac{17}{35}\).
(ii) Calculate the expected value \(E(X) = \frac{108}{70} = \frac{54}{35} \approx 1.543\). The variance is given by: