The possible values of the random variable X are 0, 1, and 2.

To find the probability distribution, consider the following cases:

1. P(X = 0): No chocolates are taken. This occurs if a toffee or boiled sweet is taken from Susan's bag and then a toffee or boiled sweet is taken from Ahmad's bag.

\(P(T, B) + P(T, T) = \frac{5}{12} \times \frac{2}{10} + \frac{5}{12} \times \frac{5}{10} = \frac{7}{24} \approx 0.292\)

\(2. P(X = 2): Two chocolates are taken. This occurs if a chocolate is taken from Susan's bag and then a chocolate is taken from Ahmad's bag.\)

\(P(C, C) = \frac{7}{12} \times \frac{4}{10} = \frac{28}{120} = \frac{7}{30} \approx 0.233\)

\(3. P(X = 1): One chocolate is taken. This is the complement of the other two probabilities.\)

\(P(X = 1) = 1 - \frac{7}{24} - \frac{7}{30} = \frac{19}{40} \approx 0.475\)

Thus, the probability distribution is: