Let \(X\) be the number of attempts Sharik makes until he gets the correct answer.

The possible values of \(X\) are 1, 2, and 3.

Probability that Sharik gets the correct answer on the first attempt (\(X = 1\)):

\(P(1) = \frac{1}{3}\)

Probability that Sharik gets the correct answer on the second attempt (\(X = 2\)):

First attempt is wrong and second attempt is correct:

\(P(2) = P(WC) = \frac{1}{3} \times \frac{1}{2} = \frac{1}{6}\)

Probability that Sharik gets the correct answer on the third attempt (\(X = 3\)):

First two attempts are wrong and third attempt is correct:

\(P(3) = P(WWC) = \frac{1}{3} \times \frac{1}{2} \times 1 = \frac{1}{6}\)

Total probability for \(X = 2\) and \(X = 3\):

\(P(2) + P(3) = \frac{1}{6} + \frac{1}{6} = \frac{1}{3}\)

Probability distribution table:

Expected value \(E(X)\):

\(E(X) = 1 \times \frac{1}{3} + 2 \times \frac{1}{3} + 3 \times \frac{1}{3} = 2\)