(i) To complete the table, calculate the sum of the numbers from Spinner A and Spinner B for each combination. For example, if Spinner A shows 1 and Spinner B shows -3, then \(X = 1 + (-3) = -2\). Complete the table similarly for all combinations.

(ii) To find the probability distribution of \(X\), count the frequency of each sum from the completed table and divide by the total number of outcomes (16). The probabilities are: \(-2: \frac{1}{16}, -1: \frac{2}{16}, 0: \frac{4}{16}, 1: \frac{3}{16}, 2: \frac{2}{16}, 3: \frac{3}{16}, 4: \frac{1}{16}\).

(iii) Calculate \(\text{Var}(X)\) using the formula \(\text{Var}(X) = E(X^2) - [E(X)]^2\). First, find \(E(X) = \sum x \cdot P(x) = 1\). Then, \(E(X^2) = \sum x^2 \cdot P(x) = \frac{62}{16}\). Thus, \(\text{Var}(X) = \frac{62}{16} - 1^2 = \frac{23}{8} = 2.875\).

(iv) To find the probability that \(X\) is even given \(X\) is positive, use conditional probability: \(P(\text{even} \mid \text{positive}) = \frac{P(\text{even and positive})}{P(\text{positive})}\). The even positive values are 2 and 4, with probabilities \(\frac{2}{16} + \frac{1}{16} = \frac{3}{16}\). The positive values are 1, 2, 3, and 4, with probabilities \(\frac{3}{16} + \frac{2}{16} + \frac{3}{16} + \frac{1}{16} = \frac{9}{16}\). Thus, \(P(\text{even} \mid \text{positive}) = \frac{3/16}{9/16} = \frac{5}{9}\).