(a) To find \(P(X = 2)\), we consider the scenarios where the highest number is 2. The possible outcomes are (2,2,2), (2,2,1), (2,1,2), (1,2,2), (2,1,1), (1,2,1), and (1,1,2). There are 7 such outcomes.

The total number of outcomes when spinning three 4-sided spinners is \(4 \times 4 \times 4 = 64\).

Thus, \(P(X = 2) = \frac{7}{64}\).

(b) To complete the probability distribution table, we need to find \(P(X = 1)\) and \(P(X = 4)\).

\(P(X = 1)\) occurs only when all spinners show 1, which is (1,1,1). Thus, \(P(X = 1) = \frac{1}{64}\).

For \(P(X = 4)\), we use the fact that the probabilities must sum to 1:

\(P(X = 4) = 1 - \left( \frac{1}{64} + \frac{7}{64} + \frac{19}{64} \right) = \frac{37}{64}\).