To solve this problem, we first need to determine the possible values of \(X\) and their probabilities.

The possible outcomes for the die are \(-1, -1, 0, 0, 1, 2\) and for the spinner are \(-1, 0, 1\). The possible values of \(X\) are the sums of these outcomes.

Possible values of \(X\) are: \(-2, -1, 0, 1, 2, 3\).

Next, we calculate the expected value \(E(X)\):

\(E(X) = \frac{-4 - 4 + 0 + 4 + 4 + 3}{18} = \frac{1}{6}\)

Now, we calculate \(\text{Var}(X)\):

\(\text{Var}(X) = \frac{8 + 4 + 0 + 4 + 8 + 9}{18} - \left(\frac{1}{6}\right)^2\)

\(= \frac{11}{6} - \frac{1}{36}\)

\(= \frac{65}{36}\)

Thus, \(\text{Var}(X) = \frac{65}{36}\) or approximately 1.81.