To express \(x^2 + 6x + 2\) in the form \((x + a)^2 + b\), we complete the square:

1. Start with the expression: \(x^2 + 6x + 2\).

2. Take half of the coefficient of \(x\), which is 6, giving 3, and square it: \(3^2 = 9\).

3. Add and subtract this square inside the expression: \(x^2 + 6x + 9 - 9 + 2\).

4. Rewrite as a perfect square: \((x + 3)^2 - 9 + 2\).

5. Simplify the constants: \((x + 3)^2 - 7\).

Thus, \(a = 3\) and \(b = -7\).