(a) To find the probability distribution of X, we consider all possible outcomes from spinning the two spinners:

(b) To find E(X), we calculate:

\(E(X) = \frac{-1 \times 1 + 0 \times 2 + 1 \times 1 + 2 \times 3 + 3 \times 2}{9} = \frac{-1 + 0 + 1 + 6 + 6}{9} = \frac{12}{9} = \frac{4}{3}\)

To find Var(X), we calculate:

\(\text{Var}(X) = \frac{(-1)^2 \times 1 + (0)^2 \times 2 + (1)^2 \times 1 + (2)^2 \times 3 + (3)^2 \times 2}{9} - (E(X))^2\)

\(= \frac{1 + 0 + 1 + 12 + 18}{9} - \left(\frac{4}{3}\right)^2 = \frac{32}{9} - \frac{16}{9} = \frac{16}{9}\)