Express \(3x^2 - 12x + 7\) in the form \(a(x + b)^2 + c\), where \(a\), \(b\), and \(c\) are constants.
Solution
To express \(3x^2 - 12x + 7\) in the form \(a(x + b)^2 + c\), follow these steps:
1. Factor out the coefficient of \(x^2\) from the quadratic and linear terms:
\(3(x^2 - 4x) + 7\)
2. Complete the square for the expression inside the parentheses:
\(x^2 - 4x = (x - 2)^2 - 4\)
3. Substitute back into the expression:
\(3((x - 2)^2 - 4) + 7\)
4. Distribute the 3 and simplify:
\(3(x - 2)^2 - 12 + 7\)
5. Combine the constants:
\(3(x - 2)^2 - 5\)
Thus, \(a = 3\), \(b = -2\), and \(c = -5\).
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