(i) Since the captain, a midfield player, must be included, we need to choose 1 player from the 3 defence players and 1 player from the 5 forward players. The number of ways to do this is given by:

\(\binom{3}{1} \times \binom{5}{1} = 3 \times 5 = 15\)

(ii) If exactly one forward player must be included, we choose 1 player from the 5 forward players. Then, we choose 2 more players from the remaining 6 players (3 defence and 3 midfield). The number of ways to do this is given by:

\(\binom{5}{1} \times \binom{6}{2} = 5 \times 15 = 75\)