To find the number of different possible selections, we use combinations to select the CDs from each category.

First, select 2 pop music CDs from 6: \\(_6C_2 = \frac{6!}{2!(6-2)!} = 15\\)

Next, select 2 jazz CDs from 3: \\(_3C_2 = \frac{3!}{2!(3-2)!} = 3\\)

Finally, select 1 classical CD from 2: \\(_2C_1 = \frac{2!}{1!(2-1)!} = 2\\)

Multiply the combinations together to find the total number of selections: \\(15 \times 3 \times 2 = 90\\)