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Nov 2008 p6 q4
2874
A builder is planning to build 12 houses along one side of a road. He will build 2 houses in style A, 2 houses in style B, 3 houses in style C, 4 houses in style D and 1 house in style E.
Four of the 12 houses will be selected for a survey. Exactly one house must be in style B and exactly one house in style C. Find the number of ways in which these four houses can be selected.
Solution
To select the houses, we need to choose:
1 house from the 2 houses in style B: \(\binom{2}{1} = 2\) ways.
1 house from the 3 houses in style C: \(\binom{3}{1} = 3\) ways.
2 more houses from the remaining 7 houses (2 in style A, 4 in style D, 1 in style E): \(\binom{7}{2} = 21\) ways.
Thus, the total number of ways to select the houses is: