(ii) To find the number of ways to choose 6 images with 2 from each folder, we calculate:

\(\binom{3}{2} \times \binom{4}{2} \times \binom{8}{2} = 3 \times 6 \times 28 = 504\)

(iii) We need to consider different combinations of choosing images such that there are at least 3 from the friends folder and at least 1 from each of the other two folders. The possible distributions are:

1. 3 from Friends, 1 from Family, 2 from Holiday:

\(\binom{8}{3} \times \binom{3}{1} \times \binom{4}{2} = 56 \times 3 \times 6 = 1008\)

2. 3 from Friends, 2 from Family, 1 from Holiday:

\(\binom{8}{3} \times \binom{3}{2} \times \binom{4}{1} = 56 \times 3 \times 4 = 672\)

3. 4 from Friends, 1 from Family, 1 from Holiday:

\(\binom{8}{4} \times \binom{3}{1} \times \binom{4}{1} = 70 \times 3 \times 4 = 840\)

Summing these possibilities gives the total number of ways:

\(1008 + 672 + 840 = 2520\)