Express \(4x^2 - 12x + 13\) in the form \((2x + a)^2 + b\), where \(a\) and \(b\) are constants.
Solution
To express \(4x^2 - 12x + 13\) in the form \((2x + a)^2 + b\), we start by expanding \((2x + a)^2\):
\((2x + a)^2 = (2x)^2 + 2 \cdot 2x \cdot a + a^2 = 4x^2 + 4ax + a^2\).
We want this to match \(4x^2 - 12x + 13\). Comparing coefficients, we have:
\(4ax = -12x\) implies \(4a = -12\), so \(a = -3\).
Substitute \(a = -3\) into \(a^2\):
\(a^2 = (-3)^2 = 9\).
Now, compare the constant terms:
\(a^2 + b = 13\) implies \(9 + b = 13\), so \(b = 4\).
Thus, the expression is \((2x - 3)^2 + 4\).
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