First, calculate the total number of ways to select 9 people from 14 without any restrictions:

\(\binom{14}{9} = 2002\).

Next, calculate the number of ways where the two particular people (say T and M) are both included in the group. If T and M are both in the group, we need to select 7 more people from the remaining 12:

\(\binom{12}{7} = 792\).

Subtract the restricted cases from the total:

\(2002 - 792 = 1210\).

Alternatively, consider the cases where neither or only one of T or M is in the group:

• Neither T nor M in the group: \(\binom{12}{9} = 220\).
• Only T in the group: \(\binom{12}{8} = 495\).
• Only M in the group: \(\binom{12}{8} = 495\).

Summing these cases gives:

\(220 + 495 + 495 = 1210\).