To divide 9 people into groups of 4, 3, and 2, we use combinations.

First, choose 4 people out of 9 for the first group: \(\binom{9}{4}\).

Then, choose 3 people out of the remaining 5 for the second group: \(\binom{5}{3}\).

The last 2 people automatically form the third group: \(\binom{2}{2}\).

Calculate each combination:

\(\binom{9}{4} = 126\)

\(\binom{5}{3} = 10\)

\(\binom{2}{2} = 1\)

Multiply these results to find the total number of ways:

\(126 \times 10 \times 1 = 1260\)