(i) We need to choose a team of 7 people with at least 3 attackers, 2 defenders, and 1 midfielder. We consider the following cases:

• 3 attackers, 2 defenders, 2 midfielders: \(\binom{6}{3} \times \binom{5}{2} \times \binom{4}{2} = 1200\)
• 4 attackers, 2 defenders, 1 midfielder: \(\binom{6}{4} \times \binom{5}{2} \times \binom{4}{1} = 600\)
• 3 attackers, 3 defenders, 1 midfielder: \(\binom{6}{3} \times \binom{5}{3} \times \binom{4}{1} = 800\)

Summing these gives the total number of ways: \(1200 + 600 + 800 = 2600\).

(ii) To divide the team of 7 into a group of 4 and a group of 3, we choose 4 people out of 7: \(\binom{7}{4} = 35\).