(i) To find the number of possible seating arrangements for the 11 passengers, we use the permutation formula \(^nP_r\), where \(n\) is the total number of seats and \(r\) is the number of passengers. Here, \(n = 17\) and \(r = 11\).

\(^{17}P_{11} = \frac{17!}{(17-11)!} = \frac{17!}{6!}\)

Calculating this gives \(4.94 \times 10^{11}\).

(ii) If 5 particular people sit in the back row, we first arrange these 5 people in the 5 seats of the back row, which can be done in \(5!\) ways.

Then, we arrange the remaining 6 passengers in the remaining 12 seats. This can be done in \(^{12}P_6\) ways.

Thus, the total number of arrangements is \(5! \times ^{12}P_6\).

\(5! = 120\)

\(^{12}P_6 = \frac{12!}{(12-6)!} = \frac{12!}{6!}\)

Calculating this gives \(79800000\).