To solve this problem, treat the 3 jazz CDs as a single unit or 'block'. This reduces the problem to arranging 9 units: 6 pop CDs, 2 classical CDs, and 1 jazz block.

The number of ways to arrange these 9 units is given by:

\(9!\)

Within the jazz block, the 3 jazz CDs can be arranged among themselves in:

\(3!\)

Therefore, the total number of arrangements is:

\(9! \times 3!\)

Calculating these factorials:

\(9! = 362,880\)

\(3! = 6\)

Thus, the total number of arrangements is:

\(362,880 \times 6 = 2,177,280\)

Alternatively, the mark scheme suggests another possible answer of 2,180,000, which might be due to rounding or approximation in a different context.