(ii) Consider the 6 tallest sopranos as a single block. This block can be arranged in a line with the remaining 4 sopranos. There are 5 blocks in total (1 block of 6 sopranos and 4 individual sopranos). The number of ways to arrange these 5 blocks is given by:

\(5!\)

Within the block of 6 sopranos, they can be arranged among themselves in:

\(6!\)

Therefore, the total number of arrangements is:

\(5! \times 6! = 86400\)

(iii) Consider the 4 tenors as a single block and the 4 basses as another block. These two blocks can be arranged in:

\(2!\)

Within the block of 4 tenors, they can be arranged among themselves in:

\(4!\)

Within the block of 4 basses, they can be arranged among themselves in:

\(3!\)

Therefore, the total number of arrangements is:

\(4! \times 3! \times 2 = 288\)