First, arrange the 5 women. There are 5! ways to arrange them.

Next, consider the positions for the man. The man cannot be at either end, so he can be placed in any of the 4 middle positions.

Thus, the total number of arrangements is given by:

\(5! \times 4 = 120 \times 4 = 480\)

Alternatively, calculate the total number of arrangements of 6 people, which is 6!. Then subtract the cases where the man is at either end:

\(6! - 2 \times 5! = 720 - 240 = 480\)