(i) Consider Jai and Kaz as a single unit or block. Similarly, each friend and his wife can be considered as a block. This results in 6 blocks to arrange. The number of ways to arrange these 6 blocks is given by:

\(6!\)

Within each block, the two people can be arranged in \(2!\) ways. Therefore, the total number of arrangements is:

\(6! \times 2^6 = 720 \times 64 = 46080\)

(ii) Jai and Kaz occupy the two middle positions, so they are fixed. The five friends can be arranged on one side in \(5!\) ways, and the five wives can be arranged on the other side in \(5!\) ways. Therefore, the total number of arrangements is:

\(5! \times 5! \times 2 \times 2 = 120 \times 120 \times 4 = 57600\)