The word 'CELESTIAL' consists of the letters: C, E, L, E, S, T, I, A, L.

We need to select 5 letters such that there is at least one E and at most one L.

Consider the scenarios:

1. One E and one L: Choose 3 more letters from the remaining 5 letters (C, S, T, I, A). This can be done in \(\binom{5}{3} = 10\) ways.
2. Two Es and one L: Choose 2 more letters from the remaining 5 letters (C, S, T, I, A). This can be done in \(\binom{5}{2} = 10\) ways.
3. One E and no L: Choose 4 more letters from the remaining 6 letters (C, S, T, I, A, L). This can be done in \(\binom{5}{4} = 5\) ways.
4. Two Es and no L: Choose 3 more letters from the remaining 6 letters (C, S, T, I, A, L). This can be done in \(\binom{5}{3} = 10\) ways.

Summing the number of ways for these scenarios gives:

\(10 + 10 + 5 + 10 = 35\)