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Nov 2012 p63 q3
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Ronnie obtained data about the gross domestic product (GDP) and the birth rate for 170 countries. He classified each GDP and each birth rate as either ‘low’, ‘medium’ or ‘high’. The table shows the number of countries in each category.
Birth rate
GDP
Low
Medium
High
Low
3
5
45
Medium
20
42
12
High
35
8
0
One of these countries is chosen at random.
Find the probability that the country chosen has a medium GDP. [1]
Find the probability that the country chosen has a low birth rate, given that it does not have a medium GDP. [2]
State with a reason whether or not the events ‘the country chosen has a high GDP’ and ‘the country chosen has a high birth rate’ are exclusive. [2]
One country is chosen at random from those countries which have a medium GDP and then a different country is chosen at random from those which have a medium birth rate.
Find the probability that both countries chosen have a medium GDP and a medium birth rate. [3]
Solution
(i) The total number of countries is 170. The number of countries with a medium GDP is \(20 + 42 + 12 = 74\). Therefore, the probability is \(\frac{74}{170} = \frac{37}{85} \approx 0.435\).
(ii) The number of countries that do not have a medium GDP is \(170 - 74 = 96\). The number of countries with a low birth rate and not a medium GDP is \(3 + 35 = 38\). Therefore, the probability is \(\frac{38}{96} = \frac{19}{49} \approx 0.396\).
(iii) The probability of a country having both a high GDP and a high birth rate is 0, as there are no such countries. Therefore, the events are exclusive.
(iv) The probability of choosing a country with a medium GDP is \(\frac{74}{170} = \frac{37}{85}\). The probability of choosing a country with a medium birth rate is \(\frac{42}{96} = \frac{7}{16}\). The combined probability is \(\frac{37}{85} \times \frac{7}{16} = \frac{287}{1360} \approx 0.211\).