(i) The total number of students studying Music is \(40 + 12 = 52\). The total number of students is 160. Therefore, the probability that a randomly chosen student is studying Music is \(\frac{52}{160} = \frac{13}{40}\) or 0.325.

(ii) To determine independence, we check if \(P(\text{boy}) \times P(\text{Music}) = P(\text{boy and Music})\).

\(P(\text{boy}) = \frac{96}{160}\) since there are \(24 + 40 + 32 = 96\) boys.

\(P(\text{Music}) = \frac{52}{160}\) as calculated earlier.

\(P(\text{boy and Music}) = \frac{40}{160}\) since there are 40 boys studying Music.

Now, \(\frac{96}{160} \times \frac{52}{160} \neq \frac{40}{160}\), so the events are not independent.