A summary of 40 values of \(x\) gives the following information:
\(\Sigma(x-k) = 520\), \(\Sigma(x-k)^2 = 9640\),
where \(k\) is a constant.
(a) Given that the mean of these 40 values of \(x\) is 34, find the value of \(k\).
(b) Find the variance of these 40 values of \(x\).
Solution
(a) The mean of the 40 values of \(x\) is given by:
\(\frac{\Sigma x}{40} = 34\)
We know \(\Sigma(x-k) = 520\), so:
\(\frac{\Sigma x - 40k}{40} = \frac{520}{40}\)
\(34 - k = 13\)
\(k = 34 - 13 = 21\)
(b) The variance is calculated using:
\(\text{Var} = \frac{\Sigma(x-k)^2}{40} - \left(\frac{\Sigma(x-k)}{40}\right)^2\)
Substitute the given values:
\(\text{Var} = \frac{9640}{40} - \left(\frac{520}{40}\right)^2\)
\(\text{Var} = 241 - 13^2\)
\(\text{Var} = 241 - 169 = 72\)
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