A summary of 50 values of x gives
\(\Sigma (x - q) = 700\),
\(\Sigma (x - q)^2 = 14235\),
where q is a constant.
(a) Find the standard deviation of these values of x.
(b) Given that \(\Sigma x = 2865\), find the value of q.
Solution
(a) To find the standard deviation, we first calculate the variance using the formula:
\(\text{Var} = \frac{\Sigma (x - q)^2}{50} - \left(\frac{\Sigma (x - q)}{50}\right)^2\)
Substitute the given values:
\(\text{Var} = \frac{14235}{50} - \left(\frac{700}{50}\right)^2\)
\(\text{Var} = 284.7 - 196 = 88.7\)
The standard deviation is the square root of the variance:
\(\text{sd} = \sqrt{88.7} \approx 9.42\)
(b) Given \(\Sigma x = 2865\), we use the equation:
\(\Sigma x - 50q = 700\)
Substitute \(\Sigma x = 2865\):
\(2865 - 50q = 700\)
Solve for \(q\):
\(50q = 2865 - 700\)
\(50q = 2165\)
\(q = \frac{2165}{50} = 43.3\)
Log in to record attempts.