(a) To find the median for machine A, arrange the data in ascending order: 0.220, 0.231, 0.231, 0.232, 0.233, 0.234, 0.235, 0.236, 0.237, 0.238, 0.239, 0.240, 0.241, 0.242, 0.243, 0.244, 0.245, 0.246, 0.247. The median is the 10th value, which is 0.238 m.
To find the interquartile range (IQR), calculate the lower quartile (LQ) and upper quartile (UQ). LQ is the 5th value: 0.231 m. UQ is the 15th value: 0.245 m. Thus, IQR = UQ - LQ = 0.245 - 0.231 = 0.014 m.
(b) For the box-and-whisker plot, use the following values for machine A: LQ = 0.231, Median = 0.238, UQ = 0.245, minimum = 0.220, maximum = 0.254. For machine B: LQ = 0.224, Median = 0.232, UQ = 0.243, minimum = 0.211, maximum = 0.256.
(c) Comparison 1: The median length of rods produced by machine A is greater than that of machine B (0.238 m vs. 0.232 m).
Comparison 2: The interquartile range for machine A is smaller than that for machine B (0.014 m vs. 0.019 m), indicating that the lengths of rods produced by machine A are less spread out.