Browsing as Guest. Progress, bookmarks and attempts are disabled.
Log in to track your work.
Nov 2016 p63 q5
2467
The tables summarise the heights, \(h\) (cm), of 60 girls and 60 boys.
Height of girls (cm)
\(140 < h \le 150\)
\(150 < h \le 160\)
\(160 < h \le 170\)
\(170 < h \le 180\)
\(180 < h \le 190\)
Frequency
12
21
17
10
0
Height of boys (cm)
\(140 < h \le 150\)
\(150 < h \le 160\)
\(160 < h \le 170\)
\(170 < h \le 180\)
\(180 < h \le 190\)
Frequency
0
20
23
12
5
On graph paper, using the same axes, draw two cumulative frequency graphs to illustrate the data.
The cave on the school trip is \(165\ \text{cm}\) high. Use your graph to estimate the percentage of girls who will be unable to stand upright.
State one advantage of using a pair of box-and-whisker plots rather than cumulative frequency graphs to compare the heights of the girls and the boys.
Solution
(i) Draw cumulative frequency graphs for both girls and boys using the given data:
Girls: Cumulative frequencies are 0, 12, 33, 50, 60.
Boys: Cumulative frequencies are 0, 20, 43, 55, 60.
Plot these points on the graph with height on the horizontal axis and cumulative frequency on the vertical axis.
(ii) To find the percentage of girls shorter than 165 cm:
From the cumulative frequency graph for girls, find the cumulative frequency at 165 cm, which is approximately 18.
Calculate the percentage: \(\frac{18}{60} \times 100 = 30\%\).
(iii) One advantage of using box-and-whisker plots is that they clearly show the median, quartiles, and range, making it easier to compare the spread and central tendency of the data for boys and girls.