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June 2005 p6 q2
2445
The following table shows the results of a survey to find the average daily time, in minutes, that a group of schoolchildren spent in internet chat rooms.
Time per day (t minutes)
Frequency
\(0 \leq t < 10\)
2
\(10 \leq t < 20\)
f
\(20 \leq t < 40\)
11
\(40 \leq t < 80\)
4
The mean time was calculated to be 27.5 minutes.
Form an equation involving \(f\) and hence show that the total number of children in the survey was 26. [4]
Find the standard deviation of these times. [2]
Solution
To find \(f\) and the total number of children:
The midpoints of the intervals are: 5, 15, 30, and 60.